if x⅓+y⅓+z⅓=0,then a)x³+y³+z³=0 b)x+y+z=3x⅓y⅓z⅓ c)x+y+z=3xyz
d)x³+y³+z³=3xyz
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c is the answer
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Answered by
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x+y+z=3xyz
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