Question

if x+y+z=0 then find the value of x^3+y^3+z^3

Answer 1

Hi friend!!

We know that

x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)

Given, x+y+z=0

x³+y³+z³-3xyz=0×(x²+y²+z²-xy-yz-zx)

x³+y³+z³-3xyz=0

x³+y³+z³=3xyz

I hope this will help you ;)