Question

if x+y+z=0 then find (y-z-x)^3/2 +(z-x-y)^3/2 +(y-z-x)^3/2

Answer 1

= (y-z-x)^3/2 + (z-x-y)^3/2 + (y-z-x)^3/2
= y^3/2 - z^3/2 - x^3/2 + z^3/2 - x^3/2 - y^3/2 + y^3/2 - z^3/2 - x^3/2
= ( +y -y +y)^3/2 + ( -z +z -z)^3/2 + ( -x -x -x )^3/2
= y^3/2 - z^3/2 - 3x^3/2
hope this helps you
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