Question

If X+Y+Z=0 then show that x^3+y^3+z^3=3xyz​

Answer 1

Step-by-step explanation:

x^3 + y^3 + z^3 - 3xyz = (x + y + z)(x^2 + y^2 + z^2 -xy -yz -xz)

putting x + y + z = 0

x^3 + y^3 + z^3 - 3xyz = 0

x^3 + y^3 + z^3 = 3xyz

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