if X + Y + Z = 0 then show that x cube + y cube+ Z cube equals to 3 x y z
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x³+y³+z³-3xyz equals to
(x+y+z) (x²+y²+z²-xy-yz-zx)
that's implies 0*(x²+y²+z²-xy-yz-zx)
equals to 0
so x³+y³+z³-3xyz equals to 0
so x³+y³+z³ equals to 3xyz
hope it helps
thanks
(x+y+z) (x²+y²+z²-xy-yz-zx)
that's implies 0*(x²+y²+z²-xy-yz-zx)
equals to 0
so x³+y³+z³-3xyz equals to 0
so x³+y³+z³ equals to 3xyz
hope it helps
thanks
Ayush062002:
this process is wrong
for doing a maths problem there are many steps this is also correct
u cant say that it is a wrong process
yes but my teacher told me that we have to solve this question by that method
in my exams i use this process and i got the full mark
i m not saying that ur process is wrong
ok
forget it
ok
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