Question

if x+y+z =0 then show that x cube + y cube +z cube is equall to 3xyz

Answer 1

x + y + z = 0

=> x + y = - z ----------(1)

On cubing both sides, we get

(x+ y) ^3 = (-z) ^3

=> x^3 + y^3 + 3xy ( x + y) = - z^3

=> x^3 + y^3 + 3xy ( - z) = - z^3 [ using equation 1]

=> x^3 + y^3 - 3xyz = - z^3

=> x^3 + y^3 + z^3 = 3xyz

Answer 2

Hope it helpfull to u