Question

if x+y+z=0
then the value of x^3+y^3+z^3-3xy

SOLUTION
x^3+y^3+z^3-3xy = (x+y+z)(x^2+y^2+z^2-xy-yz-zx)

x^3+y^3+z^3-3xy = (0)(x^2+y^2+z^2-xy-yz-zx)

x^3+y^3+z^3-3xy = 0

since, x^3+y^3+z^3 = 3xy

Is this what you were looking for "tprusty80"​

Answer 1

Step-by-step explanation:

Hello Mate.

Here is your answer.

Thankyou

Have A Nice Day