If (x+y+z)=0 then value of x^2(y+z)+y^2(z+x)+z^2(x+y)+3xyz
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i hope u get itt
try to ynderstand well
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Step-by-step explanation:
x+y+z=0
y+z=-x
x+z=-y
x+y=-z
--->x^2(y+z)+y^2(z+x)+z^2(x+y)+3xyz
now putting the values
we get ,
--->-x^3-y^3-z^3+3xyz
[as x^3+y^3+z^3=3xyz when x+y+z=0]
so ,
--->-(x^3+y^3+z^3)+3xyz
--->-3xyz+3xyz
--->0
Hope it helps
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