Question

If (x+y+z)=0 then value of x^2(y+z)+y^2(z+x)+z^2(x+y)+3xyz

Answer 1

Answer:

i hope u get itt

try to ynderstand well

Answer 2

Answer:

Your answer is : 0

Step-by-step explanation:

x+y+z=0

y+z=-x

x+z=-y

x+y=-z

--->x^2(y+z)+y^2(z+x)+z^2(x+y)+3xyz

now putting the values

we get ,

--->-x^3-y^3-z^3+3xyz

[as x^3+y^3+z^3=3xyz when x+y+z=0]

so ,

--->-(x^3+y^3+z^3)+3xyz

--->-3xyz+3xyz

--->0

Hope it helps