Question

if x+y+z=0 then (x+y)*3 + (y+z)*3 +(z+x)*3​

Answer 1

Step-by-step explanation:

x+y+z=0⇒x+y=−z

Cubing on both sides,

(x+y)3 =(−z)3

⇒x3+y3 +3xy(x+y)=z3

⇒x3+y3 +3xy(−z)=−z3

⇒x3+y3−3xyz+z3 =0

∴x3+y3+z3=3xyz

Hence Proved.

√\________Anushka❤❤

Answer 2

USING PROPERTY-->

a³+b³+c³=3abc

if a+b+c=0

SO AS ITS ALREADY GIVEN THAT x+y+z=0

SO,

3 × (0+0)³+(0+0)³+(0+0)³

3×(0+0+0)

ANY NO. MULTIPLIED TO 0=0

THEREFORE THE ANSWER IS ZERO

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