if x+y+z=0,then x3+y3+z3=
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Answer:
Step-by-step explanation:
x+y+z=0⇒x+y=−z
Cubing on both sides,
(x+y)
3
=(−z)
3
⇒x
3
+y
3
+3xy(x+y)=z
3
⇒x
3
+y
3
+3xy(−z)=−z
3
⇒x
3
+y
3
−3xyz+z
3
=0
∴x
3
+y
3
+z
3
=3xyz
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