Question

If x+ y + z = 0, Then x3 + y3 + z3 is equal to

(a) 3xyz
(b) -3xyz
(c) xy
(d) -2xy​

Answer 1

Step-by-step explanation:

x+y+z= 0 ➡️ x+y= -z

(x+y)³= (-z)³

x³+y³+3xy(x+y)=-z3

x³+y³+3xy(-2)=-z³3 [x+y=-z]

x³+y³-3xyz=-z³

x³+y³+z³= 3xyz

Hence, x+y+z= ➡️ 0x³+y³+z³= 3xyz

(a) 3xyz is the correct option.

Answer 2

Answer:

xyz

Step-by-step explanation:

It is an identity.

X3+y3+z3=(x+y+z)(x2+y2+z2-xy-yz-zx)

If x+y+z=0 then whole expression ll be 0