Question

if x+y+z=0, then xsq3+ysq3+zsq3=​

Answer 1

Answer:

x+y+z=0⇒x+y=−z

Cubing on both sides

,(x+y) 3 =(−z) 3

⇒x 3 +y 3+3xy(x+y)=3

⇒x 3 +y 3 +3xy(−z)=−z 3

⇒x 3+y 3 −3xyz+z

3 =0∴x 3 +y 3 +z 3 =3xyz

Answer 2

Answer:

0 (ans.)

Step-by-step explanation:

= xsq3 + ysq3 + zsq3

= we take common sq3 from xsq3 + ysq3 + zsq3

So,

= sq3 ( x + y + z )

since, we know that x + y + z = 0

So,

= sq3 ( 0 )

= sq3 × 0

= 0 ( ans. )

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