Question

if x+y+z=0,what is the value of x3+y3+z3-3xyz-(xyz)​

Answer 1

Answer:

If x + y + z = 0, then x3 + y3 + z3 – 3xyz = 0 or x3 + y3 + z3 = 3xyz. (i) We have to find the value of 483 – 303 – 183 = 483 + (–30)3 + (–18)3.

hope it is helpful

make me as brineliest