if x+y+z=0,x square + y square +z square=12, then the value of xy+yz+zx
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Answered by
5
x square + y square + z square =12
x square = y square = z square = 2square
xy+yz+zx=48
x square = y square = z square = 2square
xy+yz+zx=48
Answered by
8
x+y+z=0
x²+y²+z²=12
we know that ,
(x+y+z)²= x²+y²+z²+2(xy+yz+zx)
0²=12+2(xy+yz+zx)
-12= 2(xy+yz+zx)
-6= (xy+yz+zx)
Hence value of xy+yz+zx is -6
x²+y²+z²=12
we know that ,
(x+y+z)²= x²+y²+z²+2(xy+yz+zx)
0²=12+2(xy+yz+zx)
-12= 2(xy+yz+zx)
-6= (xy+yz+zx)
Hence value of xy+yz+zx is -6
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