if x+y+z=0,x^+ y^ +z^=12, then the value of xy+yz+zx
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x+y+z=0
x²+y²+z²=12
we know that ,
(x+y+z)²= x²+y²+z²+2(xy+yz+zx)
0²=12+2(xy+yz+zx)
-12= 2(xy+yz+zx)
-6= (xy+yz+zx)
Hence value of xy+yz+zx is -6
x+y+z=0
x²+y²+z²=12
we know that ,
(x+y+z)²= x²+y²+z²+2(xy+yz+zx)
0²=12+2(xy+yz+zx)
-12= 2(xy+yz+zx)
-6= (xy+yz+zx)
Hence value of xy+yz+zx is -6
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