If x+y+z=0and x 2 +y 2 +z 2 =12 find the valueof xy+yz+zx
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since, (x + y + z)² = x² + y² + z² + 2(xy +yz +zx)
according to question
0 = 12 + 2(xy+yz+zx)
∴ xy + yz +zx = -6
according to question
0 = 12 + 2(xy+yz+zx)
∴ xy + yz +zx = -6
vaishu12:
nice answer shikar
Answered by
0
Answer:
-6
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