If x+y+z=0thenfindxpower3 +ypower3 +zpower3
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→ Given : ( x + y + z ) = 0
♦ Isolate 'z' on the other side and cube :
→ ( x³ + y³ + 3xy( x + y ) ) = -z³
→ ( x³ + y³ + z³ ) = 3xy( - x - y - z + z ) = 3xyz
→ [ x³ + y³ + z³ ] = 3xyz
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→ Given : ( x + y + z ) = 0
♦ Isolate 'z' on the other side and cube :
→ ( x³ + y³ + 3xy( x + y ) ) = -z³
→ ( x³ + y³ + z³ ) = 3xy( - x - y - z + z ) = 3xyz
→ [ x³ + y³ + z³ ] = 3xyz
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