Question

If x + y + z = 1, then 1-3x^2 -3y^2-3z^2 + 2x^3 + 2y^3 +2z^3 is equal to

Answer 1

see buddy u can take whole cube both the sides and open the expansion of(x+y+z)^3so from here u can get the value in quadratic and replace that value of x^3+y^3+z^3 from the above equation.
first, u try yourself if u cant get the answer than comment below. I will write the answer for u