Question

if x+y+z=1,xy+yz+zx=1and xyz=-1.find the value of x³+y³+z³

Answer 1

Answer: -5

Step-by-step explanation:

(x+y+z)^2= x^2+y^2+z^2+2xy+2yz+2xz

(1)^2=x^2+y^2+z^2+2(xy+yz+zx)

***x^2+y^2+z^2 = 1 - 2 = -1***

x^3+y^3+z^3=(x+y+z)(x^2+y^2+z^2-xy-yz-zx)+3zyx

                     =(1)*[-1+(-1)]+3(-1)

                     = -2-3

                     = -5

I hope u got ur answer.....