If x+y+z=1,xy+zx+yz=-1and xyz=-1find the value of x³+y³+z³
Answers
Answered by
2
Answer:
(x+y+z)^3=x^3+y^3+z^3+3(xy+yz+zx+xyz)
(1)^3=x^3+y^3+z^3+3(-1-1)
1=x^3+y^3+z^3-6
x^3+y^3+z^3=7
Similar questions