) If x + y+ z =10 and ^ + ^2+^2=40,then find the value of (i) xy + yz + zx (ii) ^3 + ^3+^3 - 3xyz
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Solution:-
(x+y+z)²=x²+y²+z²+2(xy+yz+zx)
10²=40+2(xy+yz+zx)
2(xy+yz+zx)=100-40=60
xy+yz+zx=30
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