if x+y+z=12 & xy+yz+zx=25 then find x^2+y^2+z^2
Answers
Answered by
1
Answer:
94
Step-by-step explanation:
x^2+y^2+z^2+2(xy+yz+zx)=(x+y+z)^2
Answered by
3
Step-by-step explanation:
x+y+z=12
And,xy+yz+zx=25
Now,
(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2zx
(12)^2=x^2+y^2+z^2+2(xy+yz+zx)
144=x^2+y^2+z^2+2(25)
144-50=x^2+y^2+z^2
Therefore , x^2+y^2+z^2=94.
Hope It Helps !!
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