If x + y +z = 12 and x^2 + y^ 2+ z^2= 44, find xy + yz+zx.
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Step-by-step explanation:
(x + y + z )²= x²+Y²+Z²+2 [ab+bc+Ca]
(12)²=44+2[ab+bc+ca]
144-44=2[ab+bc+Ca]
100/2 = ab+bc+Ca
50 = xy + yz+zx
Answered by
4
Answer:
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