Question

If x + y +z = 12 and x^2 + y^ 2+ z^2= 44, find xy + yz+zx.​

Answer 1

Step-by-step explanation:

(x + y + z )²= x²+Y²+Z²+2 [ab+bc+Ca]

(12)²=44+2[ab+bc+ca]

144-44=2[ab+bc+Ca]

100/2 = ab+bc+Ca

50 = xy + yz+zx

Answer 2

Answer:

click the pic:-)

Step-by-step explanation:

follow the steps