Question

If x y z=12 and x2 y2 z2=70 then find the value of x3 y3 z3-3xyz

Answer 1

x2 y2 z2 are its power or You mean to say that 2x 2y 2z.

Answer 2

Thank you for asking this question:

Given,

a + b + c  = 12 and a² + b² + c² = 70

(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca

= (12)² = 70 + 2 (ab + bc + ca)

= 2 (ab + bc + ca) = 144 - 70 = 74

= ab + bc + ca = 37

a³ + b³ + c³ - 3abc = (a+b+c) (a² +b² + c² - ab - bc - ca)

= (12) (70-37) = 12 x 33 = 396

So the value of a³ + b³ + c³ - 3abc is 396