If x+y+z=12 and xy+yz+zx=25,then find x2+y2+z2?
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Answered by
8
The answer is on the sheet .
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Swapnil11111:
sorry
answer is 94
it is 25 × 2
means 144-50
= 94
Answered by
7
Hi ,
x + y + z = 12 ----( 1 )
xy + yz + zx = 25 ---( 2 )
we know the algebraic identity ,
( x + y + z )² = x² + y² + z² + 2xy + 2yz + 2zx
( x + y + z )² = x² + y² + z² + 2( xy + yz + zx )
( 12 )² = x² + y² + z² + 2 × 25
144 - 50 = x² + y² + z²
Therefore ,
x² + y² + z² = 94
I hope this helps you.
:)
x + y + z = 12 ----( 1 )
xy + yz + zx = 25 ---( 2 )
we know the algebraic identity ,
( x + y + z )² = x² + y² + z² + 2xy + 2yz + 2zx
( x + y + z )² = x² + y² + z² + 2( xy + yz + zx )
( 12 )² = x² + y² + z² + 2 × 25
144 - 50 = x² + y² + z²
Therefore ,
x² + y² + z² = 94
I hope this helps you.
:)
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