if x+y+z = 12, xy+yz+zx =44and xyz =48 then what is the value of x3+y3+z3?
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Answered by
1
Answer:
x+y+z = 12
3x+3y+3z = 3( x+y+z) = 3×12 = 36
hope it will help you........
Answered by
1
Answer:
3x+3y+32=3(x+y+z)=3*12=36
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