Math, asked by navisandhu1198, 10 months ago

if x+y+z = 12, xy+yz+zx =44and xyz =48 then what is the value of x3+y3+z3?

Answers

Answered by sanika123481
1

Answer:

x+y+z = 12

3x+3y+3z = 3( x+y+z) = 3×12 = 36

hope it will help you........

Answered by Dheerajkumarbind44
1

Answer:

3x+3y+32=3(x+y+z)=3*12=36

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