if x+y+z=15 and xy=2 yz=3 and xz=4 then find the value of x^2+y^2+z^2
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x+y+z=15
square both-side method
or,(x+y+z)²=225
or,x²+y²+z²+2(xy+yz+zx)=225*
or,x²+y²+z²+2(2+3+4)=225
or, x²+y²+z²=225-18
.:x²+y²+z²=207
It is your answer.
*It's a formula,you have to remember.
Hope you understand.
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