Math, asked by rose3820, 1 month ago

if x+y+z=15 and xy=2 yz=3 and xz=4 then find the value of x^2+y^2+z^2​

Answers

Answered by afdwl
0

Answer:

Step-by-step explanation:

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Answered by Anonymous
0

Answer:

x+y+z=15

square both-side method

or,(x+y+z)²=225

or,x²+y²+z²+2(xy+yz+zx)=225*

or,x²+y²+z²+2(2+3+4)=225

or, x²+y²+z²=225-18

.:x²+y²+z²=207

It is your answer.

*It's a formula,you have to remember.

Hope you understand.

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