if x+y+z= 15 and xy + yz + zx = 71. Find x2 + y2 + z2
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Answered by
0
Answer:
83
Step-by-step explanation:
x=3
y=5
Z=7
x+y+z= 15
3+5+7=15
xy + yz + zx = 71
3*5 + 5*7 + 7*3 = 71
15+35+21 = 71
x2 + y2 + z2=?
3²+5²+7²
9+25+49 = 83
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