Question

if x+y-z=2,y+z-x=4 and z+x-y=6, find the value of 2y²z²+2z²x²+2x²y²-x⁴-y⁴-z⁴​

Answer 1

Answer:

So x²+y²+z² = -2(xy+yz+zx) So (x²+y²+z²)²=4( x²y²+y²z²+z²x²+2xyz(x+y+z)) .. {x+y+z=0) (x²+y² +z²)²=x⁴+y⁴+z⁴ +2x²y² +2y²z²+2z²x²

Step-by-step explanation:

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