Question

if x+y+z=20 and xy+yz+zx=100 then find the value of x*x+y*y+z*z​

Answer 1

Answer:

300

Step-by-step explanation:

x + y + z = 20

x + y + z = 20So, (x + y + z)² = x²+y²+z² + xy + yz + zx

x + y + z = 20So, (x + y + z)² = x²+y²+z² + xy + yz + zx(20)² = x²+ y²+z² + 100

x + y + z = 20So, (x + y + z)² = x²+y²+z² + xy + yz + zx(20)² = x²+ y²+z² + 100 (Since x+y+z = 20 and xy +yz + zx = 100)

x + y + z = 20So, (x + y + z)² = x²+y²+z² + xy + yz + zx(20)² = x²+ y²+z² + 100 (Since x+y+z = 20 and xy +yz + zx = 100)400 = x² +y²+ z² + 100

x + y + z = 20So, (x + y + z)² = x²+y²+z² + xy + yz + zx(20)² = x²+ y²+z² + 100 (Since x+y+z = 20 and xy +yz + zx = 100)400 = x² +y²+ z² + 100Therefore, x²+y²+ z² = 300

x + y + z = 20So, (x + y + z)² = x²+y²+z² + xy + yz + zx(20)² = x²+ y²+z² + 100 (Since x+y+z = 20 and xy +yz + zx = 100)400 = x² +y²+ z² + 100Therefore, x²+y²+ z² = 300Hope it Helps you...

x + y + z = 20So, (x + y + z)² = x²+y²+z² + xy + yz + zx(20)² = x²+ y²+z² + 100 (Since x+y+z = 20 and xy +yz + zx = 100)400 = x² +y²+ z² + 100Therefore, x²+y²+ z² = 300Hope it Helps you...Please mark me as brainliest