Question

If x+y+z=3, x+2y+3z=4, x+4y+9z=6, then :

(y, z) ≡

A) (−1, 0) B) (1, 0) C) (1, −1) D) (−1, 1)​

Answer 1

Answer:

Option B is correct.

Step-by-step explanation:

x+y+z = 3. equation 1

x+2y+3z = 4. equation 2

x+4y+9z = 6. equation 3

On subtracting equation 1 from equation 2 -

y+2z = 1

y = 1-2z. equation 4

On subtracting equation 2 from equation 3 -

2y+6z = 2

y+3z = 1. (divided by 2)

1-2z+3z = 1. (putting equation 4)

z = 1-1 = 0

Therefore y = 1-2×0= 1-0 = 1

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