Math, asked by jay200325, 9 months ago

If x+y+z=3, x+2y+3z=4, x+4y+9z=6, then :

(y, z) ≡

A) (−1, 0) B) (1, 0) C) (1, −1) D) (−1, 1)

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If x+y+z=3, x+2y+3z=4, x+4y+9z=6, then :(y, z) ≡A) (−1, 0) B) (1, 0) C) (1, −1) D) (−1, 1)​

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If x+y+z=3, x+2y+3z=4, x+4y+9z=6, then :

(y, z) ≡

A) (−1, 0) B) (1, 0) C) (1, −1) D) (−1, 1)