Question

If x+y-z=4 and x^2+y^2+z^2=30,then find the value of xy-yz-zx

Answer 1

Answer:

-7

Step-by-step explanation:

  (x+y-z)² = x² + y² + z² + 2xy - 2yz - 2xz

         (4)² = 30 + 2(xy - yz - xz)

   16 - 30 = 2(xy - yz - xz)

      -14/2 = xy - yz - zx

xy -yz -zx = -7

Hope it helps !!

Plz mark brainliest !!