If x+y+z=4 and x^2+y^2+z^2= 6 then maximum value of z is
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If x+y-z=4, x²-y²+z²=-4, and xyz=6, then what is (x, y, z)?
Try to pick solution from : xyz = 6= 1 * 2 * 3 , Now Possible combinations for (x, y, z) becomes (1, 2 , 3), (1, 3, 2), (2, 1, 3), (2, 3, 1), (3, 1, 2), (3, 2, 1), but if we try these combinations in x+y-z=4 and x²-y²+z²=-4, only one combinations satisfies it andi.e. ( 2, 3, 1). Hence Answer.
I hope this will help you
If x+y-z=4, x²-y²+z²=-4, and xyz=6, then what is (x, y, z)?
Try to pick solution from : xyz = 6= 1 * 2 * 3 , Now Possible combinations for (x, y, z) becomes (1, 2 , 3), (1, 3, 2), (2, 1, 3), (2, 3, 1), (3, 1, 2), (3, 2, 1), but if we try these combinations in x+y-z=4 and x²-y²+z²=-4, only one combinations satisfies it andi.e. ( 2, 3, 1). Hence Answer.
I hope this will help you
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