if x+y+z=4 and x2+y2+z2=10, find the value of xy+yz+zx
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Answer:
(x+y+z)²=x²+y²+z²+2xy+2yz+2zx
4²=10+2(xy+yz+xz)
16-10/2=xy+yz+xz
xy+yz+xz=3
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Answer
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Answer =3
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