Question

If x + y – z = 4 and x² + y² + z² = 38, then find the value of xy – yz – zx.

Answer 1

xy - yz - zx = - 11

Explanation:

Given x + y - z = 4

(x + y - z) ² = 16

x ² + y ² + z ² + 2 (xy - yz - zx) = 16 --------------(1)

We know that x ² + y ² + z ² = 38. Substituting this in equation 1, we get:

38 + 2 (xy - yz - zx) = 16

2 (xy - yz - zx) = - 22

(xy - yz - zx) = - 22/ 2 = - 11

Answer 2

Answer:

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