Math, asked by hemangrattra22, 3 months ago

If x + y + z = 5 and x^2 + y^2 + z^2 = 13 then xy + yz + zx = ?

Answers

Answered by agrimkingrevanch
1

Answer:

Given,

x−y+z=5 and x

2

+y

2

+z

2

=49

We know,

(a+b+c)

2

=a

2

+b

2

+c

2

+2(ab+bc+ca)

Here,

a=x

b=−y

c=z

Thus,

=>(x−y+z)

2

=x

2

+y

2

+z

2

+2(−xy−yz+zx)

=>5

2

=49+2(−xy−yz+zx)

=>−2(−xy−yz+zx)=49−25

=>(−xy−yz+zx)=−

2

24

=>(−xy−yz+zx)=−12

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