Question

If x+y+z =5 and x² +y²+z²=49,find the value of xy+yz+zx​

Answer 1

Answer:

i hope you are satisfied with my solution

Answer 2

Answer:

hey mate here is ur ans...☺❤❤

x+y+z=5

$\frac{x}{y}{z} = 49$

${x+y+z}^{2} = {x}^{2} +{y}^{2} + {z }^{2} + 2xy + 2xz + 2yz$

${5}^{2} = 49 + 2xy + 2xz + 2yz$

25-49=2(xy+yz+zx)

-12=xy+yz+zx

hope it helps u ☺❤