Question

If x+y+z=5 and xy+yz+zx =8, then find the value of x^3+y^3+z^3-3xyz

Answer 1

Answer:

5

Step-by-step explanation:

(x+y+z)²= (x²+y²+z²) +2(xy+yz+zx)

(5)²= (x²+y²+z²) +2(8)

25 = (x²+y²+z²) +16

25-16 = (x²+y²+z²)

9 = (x²+y²+z²)

x³+y³+z³-3xyz= (x+y+z) [(x²+y²+z²)-(xy+yz+zx)]

= 5 [9-8]

= 5

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