If x +Y+Z=5 FIND VALUE OF X³+Y³+15XY-125
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Answer:
x³+y³+15xy-125
=x³ + y³ +3 xy ×5 - 125
=x³ + y³ +3xy(x+y) - (5)³
= (x+y) ³ - (5)³
=(5)³ - (5)³
=0...ans
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Answered by
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Step-by-step explanation:
The value of x³+y³+15xy-125
The value of x³+y³+15xy-125= 0
Step-by-step explanation:
Given x+y = 5 ---(1)
On cubeing both sides of the equation (1), we get
(x+y)³ = 5³
=> x³+y³+3xy(x+y)=125
=> x³+y³+3xy(5)=125
/* from(1)*/
=> x³+y³+15xy = 125
=> x³+y³+15xy-125 = 0
Therefore,
The value of x³+y³+15xy-125
= 0
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