Question

If x+y+z=5,xy+yz+xx=8 and (x+y)(y+z)(z+x)=36,then xyz=?

Answer 1

Step-by-step explanation:

x+y=5-z

y+z=5-x

z+x=5-y

(x+y)(y+z)(z+x)=36

=>(5-z)(5-y)(5-x)=36

=>(25-5y-5z+zy)(5-x)=36

=>(125-25y-25z+5zy-25x+5xy+5yz-xyz)=36

=>125-25(x+y+z)+5(xy+yz+zx)-xyz=36

=>125-(25×5)+5(8)-xyz=36

=>125-125+40-xyz=36

=>(-xyz)=(-4)

=>xyz=4