If x + y + z = 6 and x² + y² + z² = 14 ,then find the value of xy + yz + zx .
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Answered by
1
Answer:
=2+6+3
=11
Step-by-step explanation:
hope it helps
Answered by
2
Answer:
(a+b+c)²= ( a²+b²+c²)+2(xy+yz+zx)
(6)²=14+2(xy+yz+zx)
36-14= 2(xy+yz+zx)
22= 2(xy+yz+zx)
(xy+yz+zx)= 11
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