Question

If x + y + z = 6 and z is an odd digit, then the three-digit number xyz is
(a) an odd multiple of 3
(b) odd multiple of 6
(c) even multiple of 3
(d) even multiple of 9​

Answer 1

Answer:

Given, x+y+z=6

⇒ The number xyz is divisible by 3 as the sum of digits is divisible by 3

Also, the last digit of the number i.e., z, is odd.

⇒The number is not divisible by 2

Hence, xyz is an odd multiplied of 3.

And option (A) is correct.

Answer 2

11+2+34+=47-46=1+98=99-99=0

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