If x+y+z=6,find the value of(2-x)^3+(2-y)^3+(2-z)^3+3(2-x)+3(2-x)(2-y)(2-z)
karthikkravindp0w5te:
wrong q
nope question is right.Checked with the teacher
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x+y+z=6
⇒(2-x)+(2-y)+(2-z) = 0
∴ (2-x)³+(2-y)³+(2-z) ³= 3[(2-x)(2-y)(2-z)]
∵ If a+b+c=0,then a³+b³+c³=3abc
⇒(2-x)³+(2-y)³+(2-z) ³- 3[(2-x)(2-y)(2-z)] =0
⇒(2-x)+(2-y)+(2-z) = 0
∴ (2-x)³+(2-y)³+(2-z) ³= 3[(2-x)(2-y)(2-z)]
∵ If a+b+c=0,then a³+b³+c³=3abc
⇒(2-x)³+(2-y)³+(2-z) ³- 3[(2-x)(2-y)(2-z)] =0
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