Question

If x+y+z=6, xy+yz+zx=11. Find the value of x²+y²+z².


please help fast! ​

Answer 1

Answer

Hey here is your answer

Step by step explanation

• so in equation it is given ( x+ y + z)=6
• so first we have to square on both sides
• (x+y+z)² = (6)²
• x²+y²+z² + 2(xy+ya+zx) =36
• x²+y²+z²+2(11)=36
• x²+y²+z²+22=36
• x²+y²+z²= 36-22
• x²+y²+z²=14

So hope it helps you!

Answer 2

Answer:

refer to attachment

Step-by-step explanation:

hope it helps