Question

if x+y+z=6, xyz=6 and xy+yz+zx=11 then find x^3+y^3+z^3
plzzz solve this question step by step it's urgent​

Answer 1

Answer:

the value of

${x}^{3} + {y}^{3} + {z}^{3} = 36$

Answer 2

Answer:

here,

x^3+y^3+z^3-3xyz

=(X+y+z)(x+y+z)^2- 3(xy+yz+zx)

= x^3+y^3+z^3-3xyz^3

=6[(6^2-3(11)]

=6(36-33)

=6*3

=18

Step-by-step explanation:

hope it helped you