If x+y+z=7 and 1/x+1/y+1/z =10/xyz ,then find the value of x^2+y^2+z^2+1
Answers
Answered by
0
Answer:
Step-by-step explanation:
Given :-
x+y+z=7
To find:-
x²+y²+z²+1 = ?
Solution:-
x²+y²+z²+1 = (x+y+z)² - 2(xy+yz+zx)
calculation:-
(xy+yz+zx)/xyz = 10xyz
(xy +yz+zx )= 10
According to question
x²+y²+z² = (x+y+z)² - 2(xy+yz+zx)
x²+y²+z² = (x+y+z)² - 2(10)
x²+y²+z² = (7)² - 2(10)
x²+y²+z² = 49-20
x²+y²+z² = 29
Similar questions