Math, asked by VismaiR, 7 months ago

if x+y-z=7 and x²+y²+z²=29 find the value of xy-yz-zx​

Answers

Answered by Anonymous
6

Step-by-step explanation:

here are your mistake

x+y+z=7

x2+y2+z2=29

so

(x+y+z) ^2

= x2+y2+z2+2(xy+yz+zx)

Answered by shivanshmehta67
1

Answer:

Bhai muje nhi ata .

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