Question

If x + y + z = 7 and x2 + y2 + z2 = 33, find the value
of x3 + y3 + 23 – 3xyz​

Answer 1

Step-by-step explanation:

w/k

(x+y+z)²=x²+y²+z²+2(cy+yz+zx)

7²=33+2(xy+yz+zx)

49-33=2(xy+yz+zx)

xy+yz+zx=8

x³+y³+z³-3xyz

=(x+y+z)(x²+y²+z²-xy-yz-zx)

=(7)(33-8)

=7.25

=175