Question

If x+y+z =7 and xy+yz+zx=6,find x²+y²+z²

Answer 1

Answer:using (a+b+c)^2

Step-by-step explanation:

(A+b+c) ^2= a^2+b^2+c^2+2ab+2bc+2ca

(7) ^2=.................... +2(6)

49=...........+12

49-12 = a^2+b^2+c^2

37=............

Answer 2

Answer:

37

Step-by-step explanation:

a+b+c²=a²+b²+c²+2ab+2bc+2ca

7²=2×6

49=12

=49-12=37